A conducting rod of length l is hinged at point O. It is free to rotate in a vertical plane. There exists a uniform magnetic field B in horizontal direction. The rod is released from the position. What is the potential difference between the two ends of the rod is proportional to? - Padhle.Online
Students' favourite free learning app with LIVE online classes, instant doubt resolution, unlimited practice for classes 6-12, personalized study app for Maths, Science, Social Studies, video e-learning, online tutorial, and more. Download Now!

A conducting rod of length l is hinged at point O. It is free to rotate in a vertical plane. There exists a uniform magnetic field B in horizontal direction. The rod is released from the position. What is the potential difference between the two ends of the rod is proportional to?

 The gravitational potential decreases to increase the kinetic energy of the rod. The equation can be written as,

mg 1/2sinθ = 1/2Iω2 = 1/2(ml2/3)ω2

⟹ ω=√3g/lsinθ

Hence the magnetic field and the direction of velocity of rods is perpendicular. 

Total potential difference developed across the ends =

B(xω)dx 

=Bl2/2√ 3g/lsinθ ∝ l3/2√sinθ.

About the Author

Principal, Babu Daudayal SVM, Mathura

Post a Comment

Cookie Consent
We serve cookies on this site to analyze traffic, remember your preferences, and optimize your experience.
Oops!
It seems there is something wrong with your internet connection. Please connect to the internet and start browsing again.
AdBlock Detected!
We have detected that you are using adblocking plugin in your browser.
The revenue we earn by the advertisements is used to manage this website, we request you to whitelist our website in your adblocking plugin.
Site is Blocked
Sorry! This site is not available in your country.