When a charged particle in motion is exposed to a magnetic field that is perpendicular to its direction of travel, we know that the particle will move in a circular motion. When a particle with charge q and mass m is exposed to a perpendicular magnetic field B and moves with velocity v, the force experienced by the particle is:= q(v×B)= q(v×B)F = qvBsinθ
A particle of charge q and mass m enters normally (at point P) in a region of the magnetic field with speed v. It comes out normally from Q after time T as shown in fig. The magnetic field Bis present only in the region of radius R and is uniform. Initial and final velocities are along the radial direction and they are perpendicular to each other. For this to happen, which of the following expression(s) is/are correct?
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Principal, Babu Daudayal SVM, Mathura